To solve the quadratic equation 2x^2 - 9x + 11 = 0 using the quadratic formula, we first identify the coefficients: a = 2, b = -9, and c = 11.
The quadratic formula states that the solutions to the quadratic equation ax^2 + bx + c = 0 are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Plugging in the coefficients, we have:
x = (-(-9) ± √((-9)^2 - 4(2)(11))) / (2(2))
Simplifying further:
x = (9 ± √(81 - 88)) / 4
= (9 ± √(-7)) / 4
Since we have a negative under the square root, the solutions will be complex numbers. Let's express the results in the form a + bi:
x = (9 ± √7i) / 4
Therefore, the solutions to the quadratic equation 2x^2 - 9x + 11 = 0 are:
x = (9 + √7i) / 4
x = (9 - √7i) / 4
Use the quadratic formula to solve the quadratic equation 222
2x^2 - 9r + 11 = 0.
Express its solutions in the form a ‡ bi
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