a = 1
b = -5
c = +10
x = [-b +/-(b^2-4ac)]/2a
Plug in the numbers. The answer will include imaginary numbers, since b^2 - 4ac is negative.
Use the quadratic formula to solve the equation
x^2-5x=-10
2 answers
x = [-b +/- sqrt(b^2-4ac)]/2a