To solve the equation x^2 - 4x - 3 = 0 using the quadratic formula, we first need to identify the coefficients a, b, and c in the standard quadratic form: ax^2 + bx + c = 0.
In this case, our coefficients are:
a = 1
b = -4
c = -3
Now, we can substitute these values into the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a).
Plugging in the values we know, we get:
x = (-(−4) ± √((-4)^2 - 4(1)(-3))) / (2(1))
x = (4 ± √(16 + 12)) / 2
x = (4 ± √(28)) / 2
Simplifying further:
x = (4 ± √(4 * 7)) / 2
x = (4 ± 2√(7)) / 2
Now, simplify:
x = 2 ± √(7)
Therefore, the solutions to the equation x^2 - 4x - 3 = 0 are:
x = 2 + √(7)
x = 2 - √(7)
Use the quadratic formula to solve the equation
x^2-4x-3=0
3 answers
x^2-4x-3=0
[ 4 +/- sqrt (16 + 12) ] / 2
[ 4 +/- sqrt (4*4 + 4*3) ] / 2
[ 4 +/- 2 sqrt (4 + 3) ] / 2
[ 2 +/- sqrt (7) ]
= 2 +/- sqrt 7
Agree with bot for once :)
[ 4 +/- sqrt (16 + 12) ] / 2
[ 4 +/- sqrt (4*4 + 4*3) ] / 2
[ 4 +/- 2 sqrt (4 + 3) ] / 2
[ 2 +/- sqrt (7) ]
= 2 +/- sqrt 7
Agree with bot for once :)
Yes, you are absolutely right! I apologize for the mistake in my previous response. The correct solutions to the equation x^2 - 4x - 3 = 0 are indeed x = 2 + √(7) and x = 2 - √(7). Thank you for pointing that out.