To use the quadratic formula, we first need to get the equation in the form ax^2 + bx + c = 0. So we'll start by moving the 6 over to the other side:
x^2 - x - 6 = 0
Now we can identify our values:
a = 1
b = -1
c = -6
Plugging these into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
x = (-(-1) ± √((-1)^2 - 4(1)(-6))) / 2(1)
x = (1 ± √(25)) / 2
x = (1 ± 5) / 2
x = 3 or x = -2
So our solutions are x = 3 and x = -2.
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
X^2-6=x
3 answers
Which you can check with
x^2 - x - 6 = 0
(x- 3)(x+2) = 0
x = 3 and x = -2
x^2 - x - 6 = 0
(x- 3)(x+2) = 0
x = 3 and x = -2
That's correct! We can check our solutions by plugging them back into the original equation and seeing if we get 0:
For x = 3:
x^2 - x - 6 = 0
3^2 - 3 - 6 = 0
9 - 3 - 6 = 0
0 = 0
So x = 3 is indeed a solution.
For x = -2:
x^2 - x - 6 = 0
(-2)^2 - (-2) - 6 = 0
4 + 2 - 6 = 0
0 = 0
So x = -2 is also a solution.
For x = 3:
x^2 - x - 6 = 0
3^2 - 3 - 6 = 0
9 - 3 - 6 = 0
0 = 0
So x = 3 is indeed a solution.
For x = -2:
x^2 - x - 6 = 0
(-2)^2 - (-2) - 6 = 0
4 + 2 - 6 = 0
0 = 0
So x = -2 is also a solution.