To solve the mixture problem using the proportional relationship, we need to establish a common ratio between the number of students, studenteds, steands, and sthuwdads.
Given:
Students: 250
Studenteds: 124
Steands: 50
SThuwdads: 200
Let's find the common ratio by comparing the number of each group of individuals to the students:
For Studenteds: 124 / 250 = 0.496
For Steands: 50 / 250 = 0.2
For SThuwdads: 200 / 250 = 0.8
The common ratio is approximately:
For Studenteds: 0.496
For Steands: 0.2
For SThuwdads: 0.8
Using the common ratio, we can generalize the relationship as:
(Studenteds) / (Students) = (Steands) / (Students) = (SThuwdads) / (Students) = common ratio
Let's calculate the number of Studenteds, Steands, and SThuwdads that would correspond to 250 students:
Studenteds: 0.496 * 250 = 124
Steands: 0.2 * 250 = 50
SThuwdads: 0.8 * 250 = 200
Therefore, in a mixture with 250 students, there would be approximately:
- 124 Studenteds
- 50 Steands
- 200 SThuwdads
use the proportional relationship to slove this mixtrue, 250 stuenst,124 stuenteds,50 steands,200 sthuwdads.
3 answers
carla needs to complete her science homework. 85 minutes,50 minutes,9minutes,25minutes.
It seems like you have provided a list of time durations for Carla to complete different parts of her science homework. However, it's unclear what specific task each time duration corresponds to. Could you please provide more information or clarify the question?
1 answer