Use the properties of operations and rules for multiplying and dividing to solve the following problem:

3/8×(−32)÷(−3)×1/8

5 answers

To solve the expression \( \frac{3}{8} \times (-32) \div (-3) \times \frac{1}{8} \), we can follow the order of operations and simplify step by step.

  1. Multiply \( \frac{3}{8} \) by \( -32 \): \[ \frac{3}{8} \times (-32) = \frac{3 \times (-32)}{8} = \frac{-96}{8} = -12 \]

  2. Now we have \( -12 \div (-3) \): \[ -12 \div (-3) = 4 \]

  3. Next, multiply by \( \frac{1}{8} \): \[ 4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2} \]

Thus, the value of the entire expression \( \frac{3}{8} \times (-32) \div (-3) \times \frac{1}{8} \) is \( \frac{1}{2} \).

solve 3/8×(−32)÷(−3)×1/8

To solve the expression \( \frac{3}{8} \times (-32) \div (-3) \times \frac{1}{8} \), let's go through it step by step.

  1. Simplify \( \frac{3}{8} \times (-32) \): \[ \frac{3}{8} \times (-32) = \frac{3 \times (-32)}{8} = \frac{-96}{8} = -12 \]

  2. Now perform the division with \(-3\): \[ -12 \div (-3) = 4 \]

  3. Finally, multiply by \( \frac{1}{8} \): \[ 4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2} \]

So the final result of \( \frac{3}{8} \times (-32) \div (-3) \times \frac{1}{8} \) is: \[ \boxed{\frac{1}{2}} \]

A recipe calls for 2 1/3 cups oatmeal. You double the recipe and then divide it evenly into 14 servings. How much oatmeal is in each serving?

To determine how much oatmeal is in each serving after doubling the recipe and dividing it into 14 servings, we can follow these steps:

  1. Convert the mixed number to an improper fraction: \[ 2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \]

  2. Double the amount of oatmeal: \[ 2 \times \frac{7}{3} = \frac{14}{3} \]

  3. Divide the total amount by the number of servings (14): \[ \text{Amount in each serving} = \frac{\frac{14}{3}}{14} \] This is equivalent to multiplying by the reciprocal of 14: \[ = \frac{14}{3} \times \frac{1}{14} = \frac{14}{42} = \frac{1}{3} \]

So, the amount of oatmeal in each serving is: \[ \boxed{\frac{1}{3}} \text{ cup} \]