To solve the expression \((−2)×(1/5)÷(2/3)×(−5/6)÷(3/4)\), we will follow the order of operations and rewrite it in a more manageable form.
First, we'll convert the division into multiplication by taking the reciprocal:
\[ (−2) \times (1/5) \times \left(\frac{3}{2}\right) \times (−5/6) \times \left(\frac{4}{3}\right) \]
Now we can multiply all the terms together. Let's group them for clarity:
\[ = (−2) \times (1/5) \times (3/2) \times (−5/6) \times (4/3) \]
Now we can multiply step-by-step. Let's deal with the fractions first.
- Multiply the numerator and denominator of the first two terms:
\[ (−2) \times (1/5) = \frac{−2}{5} \]
- Multiply \(\frac{−2}{5}\) by \(\frac{3}{2}\):
\[ \frac{−2}{5} \times \frac{3}{2} = \frac{−2 \times 3}{5 \times 2} = \frac{−6}{10} = \frac{−3}{5} \]
- Now, multiply \(\frac{−3}{5}\) by \(\frac{−5}{6}\):
\[ \frac{−3}{5} \times \frac{−5}{6} = \frac{(−3) \times (−5)}{5 \times 6} = \frac{15}{30} = \frac{1}{2} \]
- Finally, multiply \(\frac{1}{2}\) by \(\frac{4}{3}\):
\[ \frac{1}{2} \times \frac{4}{3} = \frac{1 \times 4}{2 \times 3} = \frac{4}{6} = \frac{2}{3} \]
Thus, the value of the expression \((−2)×(1/5)÷(2/3)×(−5/6)÷(3/4)\) is:
\[ \frac{2}{3} \]