Use the properties of operations and rules for multiplying and dividing to solve: (- 2)(1/5) / (2/3) * (- 5/6) / (3/4)

(1 point)

8 answers

To solve the expression (- 2)(1/5) / (2/3) * (- 5/6) / (3/4), we can follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) and use the properties of operations and rules for multiplying and dividing.

First, let's simplify the divisions from left to right:

(- 2)(1/5) / (2/3) = (-2) * (1/5) * (3/2) = -3/5

Next, simplify the divisions from left to right:

(- 5/6) / (3/4) = (-5/6) * (4/3) = -20/18 = -10/9

Finally, multiply the simplified divisions:

-3/5 * (-10/9) = 30/45 = 2/3

The simplified result of the expression is 2/3.
Use the properties of operations and rules for multiplying and dividing to solve: (9) / (5/4) * (7/9)(- 5) / (7/2)

(1 point)
To solve the expression (9) / (5/4) * (7/9)(- 5) / (7/2), we can follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) and use the properties of operations and rules for multiplying and dividing.

First, let's simplify the divisions from left to right:

(9) / (5/4) = 9 * (4/5) = 36/5

Next, multiply the fractions from left to right:

(7/9)(- 5) = (7 * -5) / 9 = -35/9

Finally, simplify the divisions from left to right:

-35/9 / (7/2) = (-35/9) * (2/7) = -70/63 = -10/9

Now, multiply the remaining fraction with the simplified expression from the previous step:

(36/5) * (-10/9) = -360/45 = -8

The simplified result of the expression is -8.
Sove this mut-step problem. A runner completes 1/2 of a 5-mile race every 8 minutes. At the same pace, how far can the runner go in 16 minutes? (1 point)
To find out how far the runner can go in 16 minutes, knowing that the runner completes 1/2 of a 5-mile race every 8 minutes, we can use the unit rate that the runner covers.

In 8 minutes, the runner covers 1/2 of a 5-mile race.
So, in 1 minute, the runner covers (1/2) ÷ 8 = 1/16 of a mile.

Therefore, in 16 minutes, the runner can cover (1/16) × 16 = 1 mile.

The runner can go 1 mile in 16 minutes.
Is itA water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days? (1 point)

O 480 gatons

O-480 gallons

80 gatons

80 gatons
To find the total change in the amount of water in the tank after 6 days, knowing that the water tank decreases by 10 gallons every 3 hours every day, we need to calculate the change in the amount of water in 6 days.

Every 3 hours, the water tank decreases by 10 gallons.
Therefore, in 24 hours (1 day), the water tank decreases by 10 × (24 ÷ 3) = 80 gallons.

After 6 days, the total change in the amount of water in the tank would be 80 × 6 = 480 gallons.

So, the correct answer is: 480 gallons.
A recipe calls for 13 of a container of yogurt. Each container of yogurt has 150 calories. The recipe makes 4 servings. Which set of calculations would give the correct number of calories per serving?(1 point)