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Use the product rule to simplify the following expression. Assume that variables represent nonnegative real numbers. sqaureroot...Asked by Unknown
Use the product rule to simplify the following expression. Assume that variables represent nonnegative real numbers.
squareroot 5x^2 times squareroot 15x
squareroot 5x^2 times squareroot 15x (Please type an exact answer using radicals as needed.)
squareroot 5x^2 times squareroot 15x
squareroot 5x^2 times squareroot 15x (Please type an exact answer using radicals as needed.)
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Answered by
GPT-4o mini
To simplify the expression \(\sqrt{5x^2} \times \sqrt{15x}\), we can use the property of square roots that states \(\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}\).
1. Combine under the square root:
\[
\sqrt{5x^2} \times \sqrt{15x} = \sqrt{5x^2 \times 15x}
\]
2. Multiply the expressions inside the square root:
\[
5x^2 \times 15x = 75x^3
\]
3. Now we have:
\[
\sqrt{75x^3}
\]
4. Factor \(75\) into \(25 \times 3\) to extract the square root:
\[
\sqrt{75x^3} = \sqrt{25 \times 3 \times x^2 \times x} = \sqrt{25} \times \sqrt{3} \times \sqrt{x^2} \times \sqrt{x}
\]
5. Simplify the square roots:
- \(\sqrt{25} = 5\),
- \(\sqrt{x^2} = x\).
Thus, we have:
\[
\sqrt{75x^3} = 5 \times \sqrt{3} \times x \times \sqrt{x} = 5x\sqrt{3x}
\]
The final simplified expression is:
\[
\boxed{5x\sqrt{3x}}
\]
1. Combine under the square root:
\[
\sqrt{5x^2} \times \sqrt{15x} = \sqrt{5x^2 \times 15x}
\]
2. Multiply the expressions inside the square root:
\[
5x^2 \times 15x = 75x^3
\]
3. Now we have:
\[
\sqrt{75x^3}
\]
4. Factor \(75\) into \(25 \times 3\) to extract the square root:
\[
\sqrt{75x^3} = \sqrt{25 \times 3 \times x^2 \times x} = \sqrt{25} \times \sqrt{3} \times \sqrt{x^2} \times \sqrt{x}
\]
5. Simplify the square roots:
- \(\sqrt{25} = 5\),
- \(\sqrt{x^2} = x\).
Thus, we have:
\[
\sqrt{75x^3} = 5 \times \sqrt{3} \times x \times \sqrt{x} = 5x\sqrt{3x}
\]
The final simplified expression is:
\[
\boxed{5x\sqrt{3x}}
\]
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