To rewrite the expression \( 8^t + 8^v \) using the product rule, we can factor out the common term.
We observe that both terms contain a factor of \( 8 \). The expression can be written as:
\[ 8^t + 8^v = 8^t(1 + 8^{v-t}) \]
or
\[ 8^v(1 + 8^{t-v}) \]
This represents a reformulation of the original expression in terms of the product of a common base raised to a power and a sum.
However, if you were looking for a specific application of the product rule from calculus for differentiation or another context, please clarify, and I can assist you further!