x^3e^y-ye^x=0
Using the product and chain rules,
3x^2 e^y + x^3 e^y y' - e^x y - e^x y' = 0
Now just solve for y'.
Use the process of implicit differentiation to find
dy/dx given that x^3e^y-ye^x=0
5 answers
Ok. How to solve it that's my issue?
oh come on. The calculus is done. The rest is just algebra I.
(x^3 e^y - e^x) y' = e^x y - 3x^2 e^y
Now just divide to get y'.
(x^3 e^y - e^x) y' = e^x y - 3x^2 e^y
Now just divide to get y'.
Divide by 0?
huh? HUH?
y' = (e^x y - 3x^2 e^y) / (x^3 e^y - e^x)
Looks like you need to review implicit differentiation. In general, y' will be an expression involving both x and y.
y' = (e^x y - 3x^2 e^y) / (x^3 e^y - e^x)
Looks like you need to review implicit differentiation. In general, y' will be an expression involving both x and y.