Use the polynomial identity  x2−a2=(x+a)(x−a)  to rewrite  x2−196 . Which polynomial does this establish?(1 point)Responsesx2−196=(x+98)(x−98)x squared minus 196 equals left parenthesis x plus 98 right parenthesis left parenthesis x minus 98 right parenthesisx2−196=(x−14)(x−14)x squared minus 196 equals left parenthesis x minus 14 right parenthesis left parenthesis x minus 14 right parenthesisx2−196=(x−98)(x−98)x squared minus 196 equals left parenthesis x minus 98 right parenthesis left parenthesis x minus 98 right parenthesisx2−196=(x+14)(x−14)

1 answer

To rewrite \( x^2 - 196 \) using the polynomial identity \( x^2 - a^2 = (x + a)(x - a) \), we identify \( a^2 \) with 196. This means \( a = 14 \) since \( 14^2 = 196 \).

Thus, we can rewrite \( x^2 - 196 \) as:

\[ x^2 - 196 = x^2 - 14^2 = (x + 14)(x - 14) \]

So the polynomial identity we established is:

\[ x^2 - 196 = (x + 14)(x - 14) \]

Looking through the responses, the correct one is:

\( x^2 - 196 = (x + 14)(x - 14) \).