To generate a Pythagorean triple, we need to find values of x and y that satisfy the equation (x^2 + y^2)^2 = (x^2 - y^2)^2 + (2xy)^2.
Let x = 7 and y = 3.
Substituting these values into the equation, we get:
(7^2 + 3^2)^2 = (7^2 - 3^2)^2 + (2*7*3)^2
(49 + 9)^2 = (49 - 9)^2 + (42)^2
(58)^2 = (40)^2 + (42)^2
3364 = 1600 + 1764
So, one of the values of the Pythagorean triple is 1,764.
Therefore, the correct answer is 3. 1,764.
Use the polynomial identity (x^2+y2)^2=(x^2−y2)^2+(2xy)^2 to generate a Pythagorean triple when x equals 7 and y equals 3. Which of the following is one of the values of the Pythagorean triple?(1 point)
1. 40
2. 21
3. 1,764
4. 1.600
1 answer