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When polonium-210 emits an alpha particle, the child isotope has an atomic mass of 206. (Polonium-210 has an atomic number of 84. When it emits an alpha particle, it loses 2 protons and 2 neutrons, resulting in an isotope with an atomic mass of \(210 - 4 = 206\) and an atomic number of \(84 - 2 = 82\), which corresponds to lead, or Pb.)
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I-131 undergoes beta-minus decay. The chemical symbol for the new element is Xe. (Iodine-131 has an atomic number of 53. Beta-minus decay involves the conversion of a neutron to a proton, which increases the atomic number by 1, resulting in an atomic number of 54, corresponding to xenon.)
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Fluorine-18 undergoes beta-plus decay. The child isotope has an atomic mass of 18. (Fluorine-18 has an atomic number of 9. Beta-plus decay involves the conversion of a proton into a neutron, which decreases the atomic number by 1, resulting in an atomic number of 8, corresponding to oxygen, but the atomic mass remains 18 since it doesn't change in this process.)
Use the periodic table and your knowledge of isotopes to complete these statements.
When polonium-210 emits an alpha particle, the child isotope has an atomic mass of ...
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I-131 undergoes beta-minus decay. The chemical symbol for the new element is ?
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Fluorine-18 undergoes beta-plus decay. The child isotope has an atomic mass of ?
1 answer