(x) = (16-x^3)^(1/3) - x
the partitions are (0,1) U (1,2)
the midpoints are at X1 = 0.5 and x2=1.5
SUM of deltaX * f(Xi) =
1 * f(0.5) + 1*f(1.5) =
f(0.5) + f(1.5) =
2.0132628476567395905687034358119 + 0.828504754
= 2.841767602
Use the mid-point rule with n = 2 to approximate the area of the region bounded by y equals the cube root of the quantity 16 minus x cubed y = x, and x = 0.
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