Let's find the result when \( 2x^3 + 5x^2 - 20x + 42 \) is divided by \( x - 2 \) using long division.
Use Long Division:
2x^2 + 9x + -12
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x - 2 | 2x^3 + 5x^2 - 20x + 42
- First Step:
- Divide the first term: \( 2x^3 \div x = 2x^2 \).
- Multiply: \( 2x^2(x - 2) = 2x^3 - 4x^2 \).
- Subtract:
2x^2
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x - 2 | 2x^3 + 5x^2 - 20x + 42
- (2x^3 - 4x^2)
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9x^2 - 20x + 42
- Second Step:
- Divide the first term: \( 9x^2 \div x = 9x \).
- Multiply: \( 9x(x - 2) = 9x^2 - 18x \).
- Subtract:
2x^2 + 9x
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x - 2 | 2x^3 + 5x^2 - 20x + 42
- (2x^3 - 4x^2)
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9x^2 - 20x + 42
- (9x^2 - 18x)
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-2x + 42
- Third Step:
- Divide the first term: \( -2x \div x = -2 \).
- Multiply: \( -2(x - 2) = -2x + 4 \).
- Subtract:
2x^2 + 9x - 2
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x - 2 | 2x^3 + 5x^2 - 20x + 42
- (2x^3 - 4x^2)
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9x^2 - 20x + 42
- (9x^2 - 18x)
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-2x + 42
- (-2x + 4)
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38
Final Answer:
The result of dividing \( 2x^3 + 5x^2 - 20x + 42 \) by \( x - 2 \) is \[ 2x^2 + 9x - 2 \quad \text{with a remainder} \quad 38. \]
So the final answer is: \[ \text{Answer: } 2x^2 + 9x - 2 \quad \text{Remainder: } 38. \]