Use the limit theorem definition of a derivative to show that given f(x)=3x^2+1, the derivative f’(x)=6x

Answer 1

(f(x+h)-f(x))/h
= ((3(x+h)^2+1)-(3x^2+1))/h
Now expand all that, divide by h, and take the limit.
Yes, it will come out to be 6x