Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that B1 is smaller than B2.)

a = 39, c = 40, angle A = 36°

angle B1 = ° angle B2 = °

angle C1 = ° angle C2 = °

b1 = b2 =

2 answers

sin 36/39 = sin C /40
C = sin^-1(40/39)sin 36 = 37
B = 180 - A -C = 107

C could also be in Quadrant 2
180 - 37 = 143
then B is 180 - 36 -143 = 1 deg

sinB/b = sin 36/39 = .0151
so
b = sin B/.0151
b1 = sin 1 /.0151 = 1.16
b2 = sin 107/.0151 = 63.3
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
a = 26, b = 32, c = 27
Similar Questions
    1. answers icon 1 answer
  1. Determine the number of positive integers n that satisfy:1/2 < n/n+1 < 99/101 I don't know how to solve this besides plugging in
    1. answers icon 2 answers
  2. Triangles Unit TestMath 8 Q2 (Pre-Algebra) / Triangles find the slant height of the square pyramid (1 point) solve 12cm 4cm 3cm
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions