Use the law of cosines to solve ABC with A=126.3, b=45, and c=62.5

Question

I did all the work to find a but my problem is finding B

a=96.2

Sin(B)=45sin126.3/96.2
B=Sin^-1(45sin126.3/96.2)
It's not going through in my calculator

Answer 1

I would use the law of sines to find angle B.

SineB/b=SinA/a

Answer 2

Sin(B)/45=126.3/96.2

im stuck there

Answer 3

B=1.03 and C=52.67