f(-1) = -4
f(0) = 9
So, the IVT says that f(x) = 0 for x somewhere in [-1,0]
use the intermediate value theorem to determine whether there is a zero
f(x) = -3^3 - 6x^2 + 10x + 9 ; [-1,0]
1 answer
f(x) = -3^3 - 6x^2 + 10x + 9 ; [-1,0]
1 answer