Use the instantaneous rate of change of f(x) = e^(5x) to find the equation of the tangent line to f(x) at x = 0.

Answer 1

f(0)=1
f'(x)=5e^(5x)
So, f'(0)=5
Now we have a point and a slope, so the line is

y-1 = 5(x-0)
or
y=5x+1

See the graphs at

http://www.wolframalpha.com/input/?i=plot+y%3De%5E(5x),y%3D5x%2B1