To determine the total bond energy in the products of the reaction \( \text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl} \), we need to calculate the bond energy for the bonds formed in the products, which are two H–Cl bonds in 2 moles of HCl.
The bond energy of an H–Cl bond is given as 427 kJ/mol.
Since there are 2 H–Cl bonds formed in the reaction, we calculate the total bond energy in the products as follows:
\[ \text{Total bond energy} = \text{Number of bonds} \times \text{Bond energy of H–Cl} \] \[ \text{Total bond energy} = 2 \times 427 , \text{kJ/mol} = 854 , \text{kJ/mol} \]
Thus, the total bond energy in the products of the reaction is 854 kJ/mol.