Use the information in the table to answer the question. Bond Bond Energy ( kJ/mol ) H-I 297 H-H 435 I-I 151 Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction. H2+I2→2HI How much total bond energy in kJ/mol is in the products of the reaction? (1 point) Responses 297 297 453 453 594 594 448

Answer 1

To calculate the total bond energy in the products of the reaction \( \text{H}_2 + \text{I}_2 \rightarrow 2 \text{HI} \), we need to consider the bond energy of the products, which are 2 moles of hydroiodic acid (HI).

The bond energy of HI is given as 297 kJ/mol. Since the reaction produces 2 moles of HI, we multiply the bond energy of one mole by 2:

\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of HI} = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]

Therefore, the total bond energy in the products of the reaction is 594 kJ/mol.

Answer 2

Use the information in the table to answer the question. Bond Bond Energy ( kJ/mol ) H–Cl 427 Cl–Cl 242 H–H 435 Hydrogen and chlorine gases react to produce hydrochloric acid according to the reaction. H2+Cl2→2HCl How much total bond energy, in kJ/mol , is in the products of the reaction? (1 point) Responses 854 854 427 427 677 677 435

Answer 3

To calculate the total bond energy in the products of the reaction \( \text{H}_2 + \text{Cl}_2 \rightarrow 2 \text{HCl} \), we need to consider the bond energy of the products, which are 2 moles of hydrochloric acid (HCl).

The bond energy of HCl is given as 427 kJ/mol. Since the reaction produces 2 moles of HCl, we multiply the bond energy of one mole by 2:

\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of HCl} = 2 \times 427 , \text{kJ/mol} = 854 , \text{kJ/mol} \]

Therefore, the total bond energy in the products of the reaction is 854 kJ/mol.