To determine the total bond energy in the products of the reaction \( \text{H}_2 + \text{Cl}_2 \rightarrow 2 \text{HCl} \), we need to calculate the bond energies of the products. Each \( \text{HCl} \) molecule contains one H–Cl bond.
The bond energy for H–Cl is given as 427 kJ/mol. Since the reaction produces 2 moles of HCl, we can calculate the total bond energy in the products as follows:
\[ \text{Total bond energy in products} = \text{number of HCl molecules} \times \text{bond energy of H–Cl} \] \[ = 2 , \text{mol} \times 427 , \text{kJ/mol} = 854 , \text{kJ/mol} \]
Therefore, the total bond energy in the products of the reaction is 854 kJ/mol.