To calculate the total bond energy in the products of the reaction \( \text{H}_2 + \text{I}_2 \rightarrow 2\text{HI} \), we need to find the bond energy of the bonds formed in the products.
In the products, there are 2 moles of \( \text{HI} \). Each \( \text{HI} \) bond has a bond energy of 297 kJ/mol. Since there are 2 bonds in the product \( \text{HI} \):
\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of HI} \] \[ \text{Total bond energy in products} = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]
Thus, the total bond energy in the products of the reaction is 594 kJ/mol.