The magnitude of the vector PQ + 4RS can be found by using the formula:
√((x2 - x1)^2 + (y2 - y1)^2)
Where x1, y1 are the coordinates of P and x2, y2 are the coordinates of Q.
Given that the coordinates of P are (1,3), the coordinates of Q are (5,6), the coordinates of R are (5,6), and the coordinates of S are (9,2), the magnitude is:
√((5-1)^2 + (6-3)^2) + 4√((9-5)^2 + (2-6)^2)
=√((4)^2 + (3)^2) + 4√((4)^2 + (-4)^2)
=√(16 + 9) + 4√(16 + 16)
=√25 + 4√32
=5 + 4√(16*2)
=5 + 4*4√2
=5 + 16√2
Therefore, the magnitude of the vector PQ + 4RS is 5 + 16√2.
Use the information from part A to find the magnitude of the vector Modifying above upper P upper Q with right arrow plus 4 Modifying above upper R upper S with right arrow.
(1 point)
Responses
2 start root 10 end root
Image with alt text: 2 start root 10 end root
7 startroot 13 endroot
Image with alt text: 7 startroot 13 endroot
start root 35 end root
Image with alt text: start root 35 end root
637
1 answer