To complete the polynomial division of \((x^2 - 4) \div (x - 1)\) using long division, follow these steps:
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Divide the leading term: Divide \(x^2\) (the leading term of the dividend) by \(x\) (the leading term of the divisor) to get \(x\).
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Multiply and subtract: Multiply \(x\) by the entire divisor \((x - 1)\): \[ x \cdot (x - 1) = x^2 - x \] Now, subtract this from the original polynomial: \[ (x^2 - 4) - (x^2 - x) = -4 + x = x - 4 \]
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Bring down the next term (if applicable): Here, there are no more terms to bring down.
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Repeat the process: Now, take \(x - 4\) and divide the leading term \(x\) by \(x\) to get 1. Multiply the entire divisor by 1: \[ 1 \cdot (x - 1) = x - 1 \] Subtract this from \(x - 4\): \[ (x - 4) - (x - 1) = -4 + 1 = -3 \]
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Final result: Now, we cannot divide anymore since the degree of the remainder (-3) is lower than the degree of the divisor (1).
Thus, the quotient is \(x + 1\) and the remainder is \(-3\).
Final answer:
The quotient is \(x + 1\) and the remainder is \(-3\).
If we express this as a fraction: \[ \frac{(x^2 - 4)}{(x - 1)} = x + 1 - \frac{3}{(x - 1)} \]
So the final result is: Quotient: \(x + 1\), Remainder: -3 (or as a fraction: \( \frac{-3}{x - 1} \)).