Use the image to answer the question.

Two side by side circles with the radius of the circle on the right 3 times the size of the radius of the circle on the left.

Tomaz draws a circle and dilates it on a photocopier using a scale factor of 3. If the original circle has a radius of 3 cm, what is the area of the dilated circle? Round your answer to the nearest tenth of a square centimeter.

(1 point)
The area of the dilated circle is approximately
square centimeters.

1 answer

To find the area of the dilated circle, we first need to determine the radius of the dilated circle.

The original circle has a radius of 3 cm. When dilated with a scale factor of 3, the new radius becomes:

\[ \text{New radius} = \text{Original radius} \times \text{Scale factor} = 3 , \text{cm} \times 3 = 9 , \text{cm} \]

Next, we calculate the area of the dilated circle using the formula for the area of a circle:

\[ \text{Area} = \pi r^2 \]

Where \( r \) is the radius of the circle. Plugging in the new radius:

\[ \text{Area} = \pi (9 , \text{cm})^2 = \pi \times 81 , \text{cm}^2 \]

Using the approximate value of \( \pi \approx 3.14 \):

\[ \text{Area} \approx 3.14 \times 81 , \text{cm}^2 \approx 254.34 , \text{cm}^2 \]

Rounding this to the nearest tenth gives:

\[ \text{Area} \approx 254.3 , \text{cm}^2 \]

Therefore, the area of the dilated circle is approximately 254.3 square centimeters.

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