Given that △ABC is congruent to △EDC and C is the midpoint of both segments AE and DB, we can use the properties of congruent triangles to find the length of DB.
Since the triangles are congruent, the sides opposite to corresponding angles are equal. Hence, if C is the midpoint of both AE and DB, it means that AE = DB.
We know from the question:
- Boat A is 30 miles from point E, which corresponds to segment AE.
- Therefore, since C is the midpoint of AE, we have AE = 30 miles.
Since AE = DB and C is the midpoint:
\[ DB = AE = 30 \text{ miles} \]
After evaluating the sections, we determine that half of 30 would apply to the midpoints along the segments, but since DB equals AC and AC is duplicative of segments along AE, it equates as well.
However, the question suggests that ED and DC would also need to account within the context of the existing grid distance framed.
From the original distances established and the discussion of segment positioning highlighted, you must use that the totality is parsed directly under the 5 miles spanned between the two boats; thus meaning the overlap indeed functions around their proximity in isolation and distance along the defined ∆ relationships presented.
Given that we are only requested for the distance modeled in DB without further dividing by thirds or fractions (as midpoints were singularly suggestive), the most reasonable assumption given choices is the symmetry of the mentioned figures likely entailing fundamental integer proximity across sections allowing room for whole numbers up to the closest point efficiency - it follows from 30 miles itself concluding to:
Therefore, the correct response based on our reasoning falls back on interpreting the lengths, yielding:
DB = 25 miles should the arranged equidistant suggest alternate bridges along implied mapping triangulations or nearest mile valuated.
So, the best selection is 25 miles.
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