To translate triangle ABC by 3 units to the left and 5 units down, we apply the following transformations to the coordinates of each vertex:
- Translate 3 units to the left: This means we will subtract 3 from the x-coordinate of each vertex.
- Translate 5 units down: This means we will subtract 5 from the y-coordinate of each vertex.
If we represent the original coordinates of points A, B, and C as \( A(x_A, y_A), B(x_B, y_B), C(x_C, y_C) \), the new coordinates will be:
- \( A'(x_A - 3, y_A - 5) \)
- \( B'(x_B - 3, y_B - 5) \)
- \( C'(x_C - 3, y_C - 5) \)
Since we don't have the original coordinates of triangle ABC given in the problem, we can't directly compute the new coordinates. However, we can check the provided answer choices to see which set of coordinates could result from this transformation.
Let's analyze the four response options step by step, assuming some hypothetical original coordinates for triangle ABC:
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Response: A′(1,10), B′(−1,6), C′(4,7)
- Notably, this transformation does not involve any subtraction by 3 or 5.
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Response: A′(1,0), B′(−1,−4), C′(4,−2)
- For point A': (1 + 3, 0 + 5) → (4, 5) is not plausible; others do not appear to follow the translation either.
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Response: A′(7,0), B′(5,−4), C′(10,−2)
- Similar to the previous responses, the transformations do not follow the rules as well.
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Response: A′(−1,2), B′(−3,−2), C′(2,0)
- For point A', (−1 + 3, 2 + 5) → (2, 7); this doesn’t match either.
Since we lack the original coordinates necessary for verifying each transformation specific to ABC, the right answer cannot be concluded from this information alone.
It appears there are no coordinate sets provided that plausibly fit the specified translation of 3 left and 5 down without knowing the original points. If you have any coordinate points for triangle ABC, I can proceed with the calculations accordingly!