Use the image to answer the question. Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ? (1 point) Responses (10, 4) left parenthesis 10 comma 4 right parenthesis (6, 0) left parenthesis 6 comma 0 right parenthesis (2, 0) left parenthesis 2 comma 0 right parenthesis (2, 12) left parenthesis 2 comma 12 right parenthesis

1 answer

To determine the new coordinates of point P′ after translating figure PQRS 6 units down and 2 units to the right, I need to know the initial coordinates of point P.

However, since the actual coordinates of point P are not provided in your message, I'll describe the translation process:

  1. Translate 2 units to the right: To move a point (x, y) 2 units to the right, you add 2 to the x-coordinate. This results in (x + 2, y).

  2. Translate 6 units down: To move a point (x, y) 6 units down, you subtract 6 from the y-coordinate. This results in (x + 2, y - 6).

If you provide the initial coordinates of point P, I can give you the exact coordinates of P′.