To determine if the graph accurately represents the piecewise function, we need to analyze the function's intervals and check the endpoints.
The piecewise function defined is:
- \( f(x) = 0.5 \) if \( 1 \leq x \leq 3 \)
- \( f(x) = 1.0 \) if \( 3 < x \leq 6 \)
- \( f(x) = 0.5x \) if \( x > 6 \)
Now, let's analyze the points:
- For \( f(x) = 0.5 \) (from \( x = 1 \) to \( x = 3 \)), the graph should include filled circles at \( (1, 0.5) \) and \( (3, 0.5) \).
- For \( f(x) = 1.0 \) (from \( x = 3 \) to \( x = 6 \)), the graph starts at \( (3, 1.0) \) with an open circle because 3 is not included in this part, and ends at \( (6, 1.0) \) with a filled circle.
- For \( f(x) = 0.5x \) (for \( x > 6 \)), the graph should be continuous starting from the value at \( x = 6 \).
Given this analysis, if there are open circles at points where needed (specifically at 3 for the transition between the second segment and the first segment), then the representation is accurate.
Thus, the correct response is:
No. There should be an open circle on the first point of two parts of the function.