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Question

there is a triangular prism with the measurements of 5.1 cm, 27.9 cm, 28.4 cm, and 30.5 cm
A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.
S.A. =__ cm squared

Answer 1

To find the surface area of a triangular prism, we calculate the area of the two triangular bases and the three rectangular sides.

Area of triangular base = 1/2 * base * height
Area of rectangular side = length * height

Base of the triangle = 5.1 cm
Height of the triangle = 27.9 cm

Area of one triangular base = 1/2 * 5.1 cm * 27.9 cm = 71.145 cm²
Area of the two triangular bases = 2 * 71.145 cm² = 142.29 cm²

Now, calculate the area of the three rectangular sides:

Length of one side = 28.4 cm
Height of the side = 30.5 cm

Area of one rectangular side = 28.4 cm * 30.5 cm = 865.4 cm²
Area of three rectangular sides = 3 * 865.4 cm² = 2596.2 cm²

Total surface area = Area of two triangular bases + Area of three rectangular sides
Total surface area = 142.29 cm² + 2596.2 cm² = 2738.49 cm²

Rounded to the nearest whole number, the wrapping paper needed to wrap the toy would be 2738 cm squared.