To find the surface area of a rectangular pyramid, you need to find the area of the base and add the areas of the four triangular faces.
First, find the area of the rectangular base:
Area = length x width
Area = 14 cm x 12 cm
Area = 168 cm^2
Next, find the area of each triangular face:
1. Front face: (1/2) x base x height
Front face area = (1/2) x 14 cm x 10.6 cm
Front face area = 74.2 cm^2
2. Back face: (1/2) x base x height
Back face area = (1/2) x 14 cm x 10.6 cm
Back face area = 74.2 cm^2
3. Left face: (1/2) x base x height
Left face area = (1/2) x 10 cm x 10.6 cm
Left face area = 53 cm^2
4. Right face: (1/2) x base x height
Right face area = (1/2) x 10 cm x 10.6 cm
Right face area = 53 cm^2
Now, add the areas of the base and the four triangular faces:
Surface area = Base area + 4(Triangular face area)
Surface area = 168 cm^2 + 74.2 cm^2 + 74.2 cm^2 + 53 cm^2 + 53 cm^2
Surface area = 422.4 cm^2
Therefore, the surface area of the rectangular pyramid is 422.4 cm squared.
Use the image to answer the question.
there is a rectangular pyramid with the measurements of 14 cm, 12 cm, 10.6 cm, and 10 cm
What is the surface area of the rectangular pyramid?
__ cm squared
1 answer