Use the image to answer the question.
There are four adjoining rectangles of the same height positioned so their vertical sides touch. The first and third rectangles from the left are the same size as each other. The second and fourth rectangles from the left are also the same size as each other but wider than the first and third. The first rectangle is labeled 7 centimeters on the left side and 2 centimeters on the bottom side. The fourth rectangle is labeled 10 centimeters on the bottom side. The second rectangle has identical small rectangles touching its top and bottom sides. The small rectangles are the same width as the second rectangle.
The net of a rectangular prism is shown. What is the surface area of the rectangular prism?
(1 point)
Responses
104 cm.2
104 cm.2
138 cm.2
138 cm.2
306 cm.2
306 cm.2
208 cm.2
1 answer
Face 1 and Face 2: The faces that are the same size as the first and third rectangles in the image are 7 cm by 2 cm. So, the area of these two faces will be 2*(7*2) = 28 cm^2.
Face 3 and Face 4: The faces that are the same size as the second rectangle in the image are 7 cm by 10 cm. So, the area of these two faces will be 2*(7*10) = 140 cm^2.
Face 5 and Face 6: The faces that are perpendicular to the image are 2 cm by 10 cm. So, the area of these two faces will be 2*(2*10) = 40 cm^2.
Adding up all the areas, the surface area of the rectangular prism is 28 + 140 + 40 = 208 cm^2.
Therefore, the correct answer is 208 cm^2.