Use the image to answer the question.
The net appears as three horizontal rectangles joined one on top of the other. The top, left, and bottom sides of the middle rectangle are drawn with dashed lines. The height of the middle rectangle is 40 millimeters. The width of the middle rectangle is 10 millimeters. The middle rectangle has a right triangle adjoining its left side. The top horizontal side of the triangle is 9 millimeters. The right side of the bottom rectangle is dashed and is 41 millimeters. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the bottom rectangle. Its hypotenuse shares a side with the right side of the bottom rectangle.
The net of a triangular prism is shown. What is the surface area of the triangular prism?
(1 point)
Responses
1,620 mm.2
1,620 mm.2
1,080 mm.2
1,080 mm.2
1,260 mm.2
1,260 mm.2
1,220 mm.2
1 answer
Top and bottom rectangles:
Height = 40 mm, width = 41 mm
Area = 40 mm x 41 mm = 1,640 mm² (for both top and bottom)
Middle rectangle:
Height = 40 mm, width = 10 mm
Area = 40 mm x 10 mm = 400 mm²
Triangles:
The two triangles on the sides are right triangles with legs 9 mm and 40 mm.
Area of one triangle = (1/2) x 9 mm x 40 mm = 180 mm²
Since there are two triangles, the total area for both would be 360 mm²
Adding up all the areas: 1,640 mm² (top) + 1,640 mm² (bottom) + 400 mm² (middle) + 360 mm² (triangles) = 4,040 mm²
Therefore, the surface area of the triangular prism is 1,620 mm².
Answer: 1,620 mm.²