To find the length of side AB in right triangle ABC using the tangent ratio, we can use the formula for tangent, which is defined as:
\[ \text{tan}(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]
In triangle ABC:
- The angle \( C \) is \( 26^\circ \).
- The base (adjacent side) \( AC \) is \( 15 \) units.
- We are looking for the opposite side \( AB \).
Using the tangent ratio:
\[ \text{tan}(26^\circ) = \frac{AB}{15} \]
Now we can solve for \( AB \):
\[ AB = 15 \cdot \text{tan}(26^\circ) \]
Now calculating \( \text{tan}(26^\circ) \):
\[ \text{tan}(26^\circ) \approx 0.4877 \]
Now substitute this value into the equation:
\[ AB \approx 15 \cdot 0.4877 \approx 7.315 \]
Rounding to two decimal places:
\[ AB \approx 7.32 \]
Therefore, the correct response is:
side AB = 7.32.