To find the coordinates of the new vertices \(E', F', G', H'\) after a dilation centered at the origin with a scale factor of 3, you need to multiply the coordinates of each vertex of the parallelogram by 3.
The original coordinates are:
- \(E(-1, 5)\)
- \(F(2, 8)\)
- \(G(4, 4)\)
- \(H(1, 1)\)
Now, we'll apply the dilation:
-
For \(E' = (3 \times -1, 3 \times 5)\):
- \(E' = (-3, 15)\)
-
For \(F' = (3 \times 2, 3 \times 8)\):
- \(F' = (6, 24)\)
-
For \(G' = (3 \times 4, 3 \times 4)\):
- \(G' = (12, 12)\)
-
For \(H' = (3 \times 1, 3 \times 1)\):
- \(H' = (3, 3)\)
So, the new vertices after dilation are:
- \(E'(-3, 15)\)
- \(F'(6, 24)\)
- \(G'(12, 12)\)
- \(H'(3, 3)\)
Thus, the correct response is: \(E'(-3, 15), F'(6, 24), G'(12, 12) \text{ and } H'(3, 3)\).