In a parallelogram, the diagonals bisect each other. Therefore, since the diagonals \(DF\) and \(EG\) intersect at point \(H\), segment \(EH\) bisects segment \(EG\).
So, the correct response is:
EH (upper E upper H)
Use the image to answer the question.
Parallelogram upper D upper E upper F upper G is shown. Diagonals are drawn from upper D to upper F and upper E to upper G to meet at upper H.
In parallelogram DEFG
, which segment bisects EG¯¯¯¯¯¯¯¯
?
(1 point)
Responses
FG¯¯¯¯¯¯¯¯
upper F upper G
EH¯¯¯¯¯¯¯¯
upper E upper H
EF¯¯¯¯¯¯¯¯
upper E upper F
DF¯¯¯¯¯¯¯¯
1 answer