In parallelogram DEFG, the diagonals intersect at point H. In a parallelogram, the diagonals bisect each other. This means that each diagonal divides the other diagonal into two equal segments.
Since the diagonals DF and EG intersect at point H, both segments EH and HG are equal. Therefore, the segment that bisects EG is EH.
So the correct answer is:
EH (E H)