To complete the proof that all three medians of a triangle intersect at one point, we can fill in the missing pieces in each step as follows:
Step 1: Draw the three medians of the triangle. Draw each median so that it starts at a vertex and ends at the midpoint of the opposite side.
Step 2: Find the coordinates of each midpoint by taking the sum of the x-coordinates and dividing by 2 and taking the sum of the y-coordinates and dividing by 2. The midpoint between (0, 0) and (b, c) is (b/2, c/2). The midpoint of (0, 0) and (a, 0) is (a/2, 0). The midpoint of (a, 0) and (b, c) is (a+b)/2, c/2.
Step 3: Find the coordinates of P, the point where the medians appear to intersect, on each median. Use the formula (1/3)(x1, y1) + (2/3)(x2, y2).
Step 4: Find the coordinates of P on the median that starts at vertex (0, 0) and ends at midpoint (a+b)/2, c/2.
(1/3)(0, 0) + (2/3)((a+b)/2, c/2) = (0, 0) + (a+b)/3, c/3) = ((a+b)/3, c/3).
Find the coordinates of P on the median that starts at vertex (a, 0) and ends at midpoint (b/2, c/2).
(1/3)(a, 0) + (2/3)(b/2, c/2) = (a/3, 0) + (b/3, c/3) = ((a+b)/3, c/3).
Find the coordinates of P on the median that starts at vertex (b, c) and ends at midpoint (a/2, 0).
(1/3)(b, c) + (2/3)(a/2, 0) = (b/3, c/3) + (a/3, 0) = ((a+b)/3, c/3).
Step 5: The coordinates of P on each median are ((a+b)/3, c/3), which proves that the three medians of this generic triangle all intersect at the same point.