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Question

Long Description (if needed) The net appears as three horizontal rectangles joined one on top of another. The sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 100 units. The height of the middle rectangle is 24 units. The middle rectangle has a right triangle adjoining its left side. The length of the hypotenuse of the triangle is 25 units and the length of its horizontal side at the top of the triangle is 7 units. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the middle rectangle. The height of the top triangle is 7 units.

The net of a triangular prism is shown. What is the surface area of the triangular prism?

(1 point)
Responses

5,684 square units
5,684 square units

5,936 square units
5,936 square units

5,668 square units
5,668 square units

5,768 square units
5,768 square units
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Answer 1

The surface area of the triangular prism can be calculated by finding the area of the two triangular faces and the three rectangular faces.

The area of each triangular face is (1/2) base x height = (1/2) x 7 x 24 = 84 square units. Since there are two triangular faces, the total area for triangular faces is 2 x 84 = 168 square units.

The area of each rectangular face can be calculated by finding the area of the rectangle and adding twice the area of the triangle attached to it. Therefore, the area of each rectangle is 100 x 24 + 2 x (1/2) x 7 x 24 = 2400 + 168 = 2568 square units. Since there are three rectangular faces, the total area for rectangular faces is 3 x 2568 = 7704 square units.

Adding the areas of the triangular faces and the rectangular faces together, we get a total surface area of 168 + 7704 = 7872 square units. So the correct answer is not listed.