Use the image to answer the question.

Question

Long Description (if needed) The net appears as three horizontal rectangles joined one on top of another. The sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 100 units. The height of the middle rectangle is 24 units. The middle rectangle has a right triangle adjoining its left side. The length of the hypotenuse of the triangle is 25 units and the length of its horizontal side at the top of the triangle is 7 units. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the middle rectangle. The height of the top triangle is 7 units.

The net of a triangular prism is shown. What is the surface area of the triangular prism?

(1 point)
Responses

5,684 square units
5,684 square units

5,768 square units
5,768 square units

5,668 square units
5,668 square units

5,936 square units

Answer 1

To find the surface area of the triangular prism, we need to calculate the area of all the faces and add them together.

1. Area of the two triangular faces:
- The triangle above the middle rectangle has a base of 25 units and a height of 7 units.
- The area of this triangle is (1/2) * 25 * 7 = 87.5 square units.
- Since there are two triangular faces, the total area for both is 2 * 87.5 = 175 square units.

2. Area of the rectangular sides:
- The middle rectangle has a width of 100 units and a height of 24 units. The area is 100 * 24 = 2400 square units.
- There are two of these rectangular sides, so the total area for both is 2 * 2400 = 4800 square units.

3. Adding all the areas together:
175 (triangular faces) + 4800 (rectangular sides) = 4975 square units.

Therefore, the surface area of the triangular prism is NOT listed as an option. The closest option is 5,684 square units.