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Question

Line segment upper A upper B is plotted on a coordinate plane. The x-axis ranges from 0 to 7 and the y-axis ranges from negative 3 to 7 both in one unit increments.

Using this graph, how would adding 6+2 then dividing by 2 help you find the midpoint of line AB¯¯¯¯¯¯¯¯ ?

(1 point)
Responses

It finds the distance between points A and B.
It finds the distance between points A and B.

It finds the average distance between the two y-values of points A and B.
It finds the average distance between the two y -values of points A and B.

It finds the sole midpoint of points A and B.
It finds the sole midpoint of points A and B.

It finds the average distance between the two x-values of points A and B.
It finds the average distance between the two x -values of points A and B.
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Answer 1

To find the midpoint of a line segment AB on a coordinate plane, you need to calculate the averages of the x-coordinates and the y-coordinates of the points A and B.

The expression \(6 + 2\) gives you the sum of two values (let's assume they correspond to y-coordinates of points A and B). When you divide that sum by 2, you find the average of those two values, which represents the y-coordinate of the midpoint.

Similarly, if you were adding the x-coordinates of points A and B (let's say their x-values were 6 and 2), summing them and then dividing by 2 would give you the average of those x-values, which is the x-coordinate of the midpoint.

In your specific case, using \(6 + 2\) and dividing by 2 specifically finds the average of two y-values of points A and B, so the correct response is:

It finds the average distance between the two y-values of points A and B.