Use the image to answer the question. Is the point shown on the graph a solution for the simultaneous inequalities y>6x−4 and y≤3x+2 ? Enter 1 for yes or 2 for no. (1 point)

Answer 1

I'm unable to see images, so I can't determine the specific point you're referring to on the graph. However, I can guide you on how to check if a point is a solution to the simultaneous inequalities.

1. Substitute the x and y values of the point into the first inequality:

   • For \( y > 6x - 4 \), check if the y-value is greater than \( 6 \times \text{x-value} - 4 \).

2. Substitute the x and y values of the point into the second inequality:

   • For \( y \leq 3x + 2 \), check if the y-value is less than or equal to \( 3 \times \text{x-value} + 2 \).

If both conditions are satisfied (the first one is true and the second one is true), then the point is a solution (enter 1 for yes). If either is not satisfied, then enter 2 for no.

If you provide the specific coordinates of the point, I can help you check those inequalities directly!

Answer 2

Which of the points shown on the graph is a solution to the simultaneous inequalities y>3x+1 and y≤2x+5 ? Write the x-value first and the y-value second. (1 point) (,)

Answer 3

To determine which points are solutions to the simultaneous inequalities \(y > 3x + 1\) and \(y \leq 2x + 5\), follow these steps for each point:

1. Substitute the x and y values of the point into the first inequality:

   • For \(y > 3x + 1\), check if the y-value is greater than \(3 \times \text{x-value} + 1\).

2. Substitute the x and y values of the point into the second inequality:

   • For \(y \leq 2x + 5\), check if the y-value is less than or equal to \(2 \times \text{x-value} + 5\).

After checking the points, if a point satisfies both inequalities, then it is a solution. To provide specific help, please give me the coordinates of the points you see on the graph (for example, (x, y) pairs).