I'm unable to see images, so I can't determine the specific point you're referring to on the graph. However, I can guide you on how to check if a point is a solution to the simultaneous inequalities.
-
Substitute the x and y values of the point into the first inequality:
- For \( y > 6x - 4 \), check if the y-value is greater than \( 6 \times \text{x-value} - 4 \).
-
Substitute the x and y values of the point into the second inequality:
- For \( y \leq 3x + 2 \), check if the y-value is less than or equal to \( 3 \times \text{x-value} + 2 \).
If both conditions are satisfied (the first one is true and the second one is true), then the point is a solution (enter 1 for yes). If either is not satisfied, then enter 2 for no.
If you provide the specific coordinates of the point, I can help you check those inequalities directly!