To find the solution of the equations \((72)x - (92) = 2y\) and \(4y = 7x - 9\), we need to manipulate and analyze both.
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First equation: \[ 72x - 92 = 2y \] Rearranging gives: \[ 2y = 72x - 92 \quad \Rightarrow \quad y = 36x - 46 \]
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Second equation: \[ 4y = 7x - 9 \] Rearranging gives: \[ y = \frac{7}{4}x - \frac{9}{4} \]
Now, both equations are in the slope-intercept form:
- \(y = 36x - 46\)
- \(y = \frac{7}{4}x - \frac{9}{4}\)
Both graphs represent straight lines, and the fact that they produce the same graph implies that they are equivalent equations.
To find the solution (intersection point), we can equate the expressions for \(y\): \[ 36x - 46 = \frac{7}{4}x - \frac{9}{4} \]
To eliminate the fraction, multiply through by 4: \[ 144x - 184 = 7x - 9 \]
Rearranging gives: \[ 144x - 7x = 184 - 9 \] \[ 137x = 175 \quad \Rightarrow \quad x = \frac{175}{137} \approx 1.286 \]
Now substituting \(x\) back into one of the equations to find \(y\): Using \(y = 36x - 46\): \[ y = 36\left(\frac{175}{137}\right) - 46 \] Calculating yields \(y = 0\).
Thus, we find the solution: The solution is \((1.286, 0)\).