Question

Use the image to answer the question.

Function 1: f(x)=4x+2

Function 2:

A diagonal line connects two data points on a coordinate plane.

Compare the two functions and identify the y-values of the y-intercepts. Which function has the smaller value?

(1 point)
Responses

Function 1: (0,−2)
; Function 2: (0,2)
. Function 2 has the smaller value.
Function 1: left parenthesis 0 comma negative 2 right parenthesis ; Function 2: left parenthesis 0 comma 2 right parenthesis . Function 2 has the smaller value.

Function 1: (−2,0)
; Function 2: (2,0)
. Function 1 has the smaller value.
Function 1: left parenthesis negative 2 comma 0 right parenthesis ; Function 2: left parenthesis 2 comma 0 right parenthesis . Function 1 has the smaller value.

Function 1: (−1,0)
; Function 2: (−1,0)
. They have identical values.
Function 1: left parenthesis negative 1 comma 0 right parenthesis ; Function 2: left parenthesis negative 1 comma 0 right parenthesis . They have identical values.

Function 1: (0,2)
; Function 2: (0,−2)
. Function 2 has the smaller value.

Answer 1

To find the y-intercept of each function, we evaluate them at \(x = 0\):

1. For Function 1: \(f(x) = 4x + 2\)
- The y-intercept is \(f(0) = 4(0) + 2 = 2\), giving the point (0, 2).

2. For Function 2, let's assume it intersects the y-axis at some point. The question implies it has a given y-value at \(x = 0\).

Assuming that the diagonal line connects two data points with one of the y-values indicating the y-intercept is negative, for example, (0, -2) as mentioned in the potential responses, we can conclude:

- Function 1: (0, 2)
- Function 2: (0, -2)

Comparing these, \(2\) from Function 1 is greater than \(-2\) from Function 2.

Thus, Function 2 has the smaller value.

So the correct response would be:

**Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smaller value.**