To find the solution of the system of equations given by \( y = 2x - 1 \) and \( y - 3 = 4x \), we first need to express both equations in a similar format.
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The first equation is already in slope-intercept form: \[ y = 2x - 1 \]
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For the second equation, we can rewrite it: \[ y - 3 = 4x \implies y = 4x + 3 \]
Now we can set the two equations equal to each other since they both equal \( y \): \[ 2x - 1 = 4x + 3 \]
Next, we solve for \( x \): \[ 2x - 4x = 3 + 1 \ -2x = 4 \ x = -2 \]
Now that we have \( x = -2 \), we can substitute this back into either equation to find \( y \). Let's use the first equation: \[ y = 2(-2) - 1 \ y = -4 - 1 \ y = -5 \]
Thus, the solution to the system of equations, which represents the point of intersection of the two lines, is: \[ (x, y) = (-2, -5) \]
Therefore, the ordered pair is \((-2, -5)\).