Use the image to answer the question.

Question

Four points and two intersecting lines are plotted on a coordinate plane. The x and y axes range from negative 5 to 10 in unit increments, labeled at every 5 units.

Which of the points on the graph is a solution for the simultaneous inequalities y>4x−2
and y≥−1/3x+2
? Enter the x-value followed by the y-value.

(1 point)
(
,
)
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Answer 1

To determine which of the points satisfies the given inequalities \( y > 4x - 2 \) and \( y \geq -\frac{1}{3}x + 2 \), we need to find an appropriate point:

1. Inequality 1: \( y > 4x - 2 \) - This represents the area above the line \( y = 4x - 2 \).
2. Inequality 2: \( y \geq -\frac{1}{3}x + 2 \) - This signifies the area above (and including) the line \( y = -\frac{1}{3}x + 2 \).

You would typically need the actual plot or coordinate points to find the correct point that meets both conditions. However, you can check each of the plotted points against the inequalities:

• For each point (x, y) that you suspect might satisfy both inequalities, plug in x into both equations and see if the resulting values of y fulfill the conditions set by both inequalities.

If you provide me the specific points plotted on the graph or the graph itself, I can assist you in determining which specific point satisfies both inequalities. Otherwise, you can follow the method outlined to check systematically and find the solution point manually.