Based on the function \( f(x) = 3(1.25)^x \), we can analyze the characteristics of this exponential growth model.
- Initial Value: At \( x = 0 \), \( f(0) = 3(1.25)^0 = 3(1) = 3 \). This means the population starts at 3.
- Growth Rate: The base of the exponent (1.25) indicates that the population will increase by 25% each day.
Expected Characteristics of the Graph:
- The graph should start at the point (0, 3) on the y-axis.
- As \( x \) increases, the y-value should increase rapidly due to the nature of exponential growth.
- By Day 6, the population should be significantly higher than the starting point.
Estimating Population Growth:
- Day 1: \( f(1) = 3(1.25)^1 \approx 3.75 \)
- Day 2: \( f(2) = 3(1.25)^2 \approx 4.688 \)
- Day 3: \( f(3) = 3(1.25)^3 \approx 5.859 \)
- Day 4: \( f(4) = 3(1.25)^4 \approx 7.36 \)
- Day 5: \( f(5) = 3(1.25)^5 \approx 9.20 \)
- Day 6: \( f(6) = 3(1.25)^6 \approx 11.5 \)
Conclusion:
To identify which graph best represents this function, look for:
- A starting point at (0, 3).
- An upward curving trend that becomes steeper as time increases.
- The value should be around 3 at Day 0 and should continue to grow towards 11.5 at Day 6.
By evaluating the responses based on these characteristics, the correct option can be determined. Unfortunately, without seeing the images, I cannot specify which option is correct, but you can use this analysis to match with the options provided.